x^2=0.02-0.02x

Solution for x^2=0.02-0.02x equation:

x^2=0.02-0.02x

We move all terms to the left:

x^2-(0.02-0.02x)=0

We add all the numbers together, and all the variables

x^2-(-0.02x+0.02)=0

We get rid of parentheses

x^2+0.02x-0.02=0

a = 1; b = 0.02; c = -0.02;
Δ = b2-4ac
Δ = 0.022-4·1·(-0.02)
Δ = 0.0804
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.02)-\sqrt{0.0804}}{2*1}=\frac{-0.02-\sqrt{0.0804}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.02)+\sqrt{0.0804}}{2*1}=\frac{-0.02+\sqrt{0.0804}}{2}
$